Advanced Algebra & Trig
Solutions to the Review 2008
1. Given the following
equation,
, find the period and amplitude. Period
is 180 and amplitude is 3.
2. Write an equation of the
cosine function with amplitude 2, period
, and phase shift
y = 2cos(2x-180)
3. Using the general
trigonometric equation
, what expression is used to determine the amplitude? period?
vertical shift? phase shift?
4. Evaluate
. This means in the 1st and 2nd
quadrants only (principal values for cosine), when is Cosine equal to 1? This occurs at 0°.
5. Find the values of
in the interval
that satisfy the
equation
. This would happen at 60° and 120°.
This is NOT a principal values problem.
6. Find the values of
for which the equation
. Sine is -1 at 270°.
7. A weighted spring oscillates freely between a
height of 10 feet below the ceiling to 2 feet below the ceiling. The amplitude of a representative
trigonometric equation would be equal to 4ft. Take 10 and subtract 2 and then divide by 2.
8. If
and
, find
. Draw your triangle in the 3rd quadrant . . . complete with
Pythagorean Thm . . . the tan = 4/3.
9. Simplify completely:
. Remember to change everything to terms of
sines and cosines . . . this simplifies to 1.
Everything cancels!! J
10. Find an expression
equivalent to
Change sec to 1/cos . . . change tan to sin/cos . . . The sine on the
denominator is the same as multiplying by 1/sin. All of this simplifies to 1/cos2 . . .
.which is equal to sec2.
11. Find the value of
if
. Draw a triangle for the sine information
(and complete Pythagorean) . . . do the same for the cosine information. Then use your formula for sum of two angles:
Sin(x + y) =
sinxcosy + cosxsiny
Answer: 56/65
12. Solve
. Solve for cosine. You’ll get cosΘ = ½ . Now Θ equals 60° and 300°.
13. Solve
for principal values
of x. Solve for x . . . you’ll have to factor out a sinx. You’ll have 2 answers . . . sinx = 0 OR
sinx = ½ . So x can equal (in the 1st and 4th
quadrants only) 0° or 30°.
14. Given
. Find
. <3, 18>
15. Write
as the sum of unit
vectors for
. Subtract “N” – “M” first . . . .<3, 2,
-8> . . . .then as sum of unit vectors . . . 3i + 2j – 8k
16. Find the magnitude of the vector represented
by the vector from
. <-3, -9, -4> . . . . then take the
square root of the sum of the squares . . . 9+81+16 = ![]()
17. A pilot flies a plane east for 200
kilometers, then
south of east for 80
kilometers. Find
the plane’s distance from the starting point. This
is a law of cosines problem. . . 
18. Given
, find a so that
the two vectors are perpendicular.
-3*4 + 2*a must equal zero . . . . so a = 6.
19. Find the cross product of
, then determine whether the resulting vector is
perpendicular to
. Set up a 3x3 matrix . . . use i, j, and k as the first row. Remember that when you get your answer . . .
check to see if a is perpendicular to your answer and if b is perpendicular to your answer.
20. Which ordered triple represents
from
to
? <3, -8, -5>
21. Write an equation of the line in
slope-intercept form whose parametric equations are
![]()
Set each
equation equal to t . . . .then cross multiply and solve. y = -2x - 1
22. Simplify
FOIL
remember that i2 = -1.
Final answer: 4 -2i
23. Find the
polar coordinates of the point with rectangular coordinates
. (2, 30°)
24. Find the rectangular coordinates of the
point with polar coordinates
(-3,0)
25. Which pair of polar coordinates also
represents the point
?
26. Rewrite the rectangular equation x = 5 in
polar form. r = 5secΘ
**The
first 13 problems on the final will be worked without a calculator. Below are a few samples of what type of
problems to expect:
27. Find sinΘ if Θ is an angle in
standard position and the point with coordinates (5,-12) lies on the terminal
side of the angle. If you plot the point (5,-12) . . . the
radius is 13. So, the sin Θ = -12/13
28. Solve the following equation for Principal
Values: cos Θ = -1/2 Principal
values are in the 1st and 2nd quadrants only for cosine.
. . so Θ = 120° and 240°.
29. On the unit circle, sin (-180) = 0
30. Which quadrant contains the terminal side if Θ
= 2Π/3? This is 2nd quadrant.
31. If cos Θ = ¼, find sec Θ. Secant
is the reciprocal of cosine . . . so secΘ = 4.
32. If Θ is in the 3rd quadrant,
and sin Θ = -4/5, find cos Θ.
Draw the triangle and complete
the Pythagorean Theorem. cosΘ =
-3/5.
33. Simplify the following:
tan2(Θ)csc2(Θ)
= 1/cos2Θ
. . . or sec2Θ.
Get rest tonight . . . Bring
this review with you tomorrow . . . don’t forget your books!!!
See you tomorrow!!!